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Tuesday, March 12, 2013

Ai9Eee

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AIEEE - 2002 Physics and Chemistry Solutions

2. 4. 5. 6.

? guck / 2 = 40 ? ?max = 80
Large aperture increases the amount of light gathered by the reach increa violateg the resolution.

KE =

1 1 2 mvesc = m( 2gR)2 = mgR 2 2

A voltmeter is a high resistance galvanometer and is consorted in match to circuit and ammeter is a low resistance galvanometer so if we connect high resistance in series with ammeter its resistance forget be much high.

7.

In coil A, B =

µ 0 2?I . 4? R

I B I R 2 ?B? ; Hence, 1 = 1 . 2 = = 1 R B2 R1 I2 2

8.

No. of images, n = (360 / ?) ? 1. As ? = 600 so n = 5

9.

V2 V2 V2 + =4 = 4P1 P1 =V /R ; P2 = (R / 2) (R / 2) R
2

10.

En = ?

13.6 13.6 ? E2 = ? 2 = 3.4eV 2 n 2
?A = 2L

11. 12.

n 2 ?A 1 = ? A = nB 1 ?B 2

A=

B=

?B = 4L

The fact that placing wax decreases the frequency of the occult split up and also the beat frequency states that the unknown fork is of higher frequency. n - 288 = 4 ? n = 292 cps y1 + y2 = a sin(?t ? kx) ? a sin(?t + kx)

13.

= ?2a cos ?t × sin kx ? y1 + y 2 = 0 at x = 0
14. 15. 16. 17. W = qV ? VA - VB = 2/20 = 0.1 V Here W is the fetch done in moving charge q from point A to B r = mv / Bq is same for both K.E. is uttermost and P.

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E minimum at mean position Angular whim = conserved

1 1 M?1 MR2 ?1 = 2mR2 ? + MR2? ? ? = 2 2 M + 4m
18. 19. The condition to avoid skidding, v = µrg = 0.6 × cl × 10 = 30 m / s v=

2gh = 2 × 10 × 20 = 20 m / s
19

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20. 21. 22. 24. 27. 28. 29. 32. 33.

K 800 ? x2 ? 2 W = ? Fdx = ? Kxdx = K ? ? = [ x 2 ? x 1 ] = [(0.15)2 ? (0.05)2 ] = 8 J 2 2 ? x1 2 2 x1 x1 ?
x2 x2

x2

Conserving Linear Momentum 2Mvc = 2Mv - Mv ? vc = v/2 It bequeath compress due to the force of attraction between 2 adjacent coils carrying current in the same direction Semiconductors atomic number 18 insulators at low temperature Neutrons cant be deflected by a magnetic field

hc / ? 0 = W0 ;

(? 0 )1 (W0 )2 4.5 = = = 2: 1 (? 0 )2 (W0 )1 2.3...If you want to get a full essay, rule it on our website: Ordercustompaper.com



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